Solve 2x² − 7x + 3 = 0.
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(2x − 1)(x − 3) = 0, so x = ½ or x = 3.
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Solve 2x² − 7x + 3 = 0.
(2x − 1)(x − 3) = 0, so x = ½ or x = 3.
The equation 2x² − 7x + k = 0 has two different real roots, and both roots are positive. Find the set of possible values of k.
Two different real roots: 49 − 8k > 0, so k < 49/8. Both positive: the product of the roots, k/2, is positive and their sum, 7/2, is already positive, so k > 0. Answer: 0 < k < 49/8.
Why the twin is harder: The twin turns “solve it” into “reason about it”: you need the discriminant and the sum and product of roots together.
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| Series | Predicted | Appeared | Hit rate |
|---|---|---|---|
| No series scored yet. After each exam series we compare the forecast with the real paper and publish the hits and the misses. | |||